## Question 906:

1## Answer:

No answer provided yet.We will use a 1-sample t-test here to test the hypothesis that the population mean is equal to 50.The test statistic is found as the difference between the sample and test mean (which is 49-50) divided by the standard error of the mean (SEM). The SEM is the standard deviation divided by the square root of the sample size : 3/SQRT(64) = .375.

So the test statistic is -1/.375 = -2.67.

To find the significance of this test statistic we need to use a t-table or use the Excel function = TDIST(2.67,63, 2) where the parameters are the test statistic, the degrees of freedom (64-1) and 2 tails for a 2-sided test of significance.

We get a 2-tailed p-value of .0097 which is less than the alpha value of .05. We then reject the null hypothesis and conclude that the population mean is not equal to 50.