## Question 686:

1## Answer:

No answer provided yet.We will want to use a 1-sample z-test against the criteria since we are given the population standard deviation.First we need to formulate the hypotheses:

- The Null hypothesis is that the average grams of fat in the orange juice is less than or equal to 2 grams: Ho: μ ≤ 2
- The alternative hypothesis is the amount of fat is greater than 2 grams : Ha: μ > 2

- Find the difference between the sample mean and test mean = 2.5-2 = .5
- Calculate the standard error of the mean (SE), which is the standard deviation divided by the square root of the sample size = 1.5/SQRT(35) = .2535
- Divide the difference from step 1 by the SE in step 2 = .5/.2535 = 1.972
- Lookup the value of z*(1.972) in a normal table or the z-score to percentile calculator to find the 1-sided probability = .0243.