## Question 678:

1## Answer:

No answer provided yet.The test statistic is z, using the normal approximation to the binomial since both np > 5 and nq >5. The test statistic is composed of the difference between the sample proportion and test proportion = .58-.60 = -.02, divided by the standard error of the mean (SE). SE is found as SQRT(pq/n) = .04. That makes the test statistic = -.2/.04 = -.5.