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Question 423:



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We'd calculate the z-score for this event, then find the probability for this normal score. To get a z-score, subtract the data-point from the mean and divide that result by the standard deviation.

  1. So (300-268)/15 = a z-score of 2.133.
  2. Now we lookup the area under the normal curve up to 2.133 standard units using the z-score to percentile calculator.  Select 1-sided area and you should get 98.35%.

So the probability a pregnancy lasts 300 days or longer is equal to 100-98.35 = 1.65%--not very many.

See also question 401

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