## Question 262:

1## Answer:

No answer provided yet.Calculate a z-score. Take the weight in question and subtract from the mean and divide that total by the standard deviation. (178-150)/15 = 1.8666, which is the z-score. Now, look up the one-sided area using the z-score to percentile calculator using 1.866, you should get about 97%. This means you'd only expect to see about 3% of the population to have a weight above 178 given the mean and standard deviation of 150 and 15 respectively.