## Question 149:

1## Answer:

No answer provided yet.I'd use a 2-sample t-test. The test-statistic is generated by subtracting the means and dividing by the standard deviation. Since the sample sizes are unequal, as well as the standard deviations, we generate a pooled standard deviation using the variance (squaring the standard deviation) and the sample size. That is: the square root of s_{1}^{2}/n_{1} + s_{2}^{2}/n_{2} = SQRT (.10^{2}/432 + .23^{2}/375) = .01285.

The difference between the means is 1.58-1.42= .16 making the test statistic = .16/.01285 = ~12.45 with around 500 degrees of freedom provides a t-statistic of 12.49. The probability associated with that value and degrees-of-freedom is well less than 1%, so we can conclude there is a difference in means between men and women at the 95% confidence level.