Login

Contact Jeff

Email Updates
About
Stats Q&A
Calculators
Tutorials
Products
Home
View All Tutorials
Fundamentals of Statistics 2: The Normal Distribution :: Above, Below and Between Probabilities
The normal curve is very helpful. If we can show that our data is like the normal curve we can use its properties to find probabilities for events to occur. All we need to know is the mean and standard deviation of a population and we're ready to start.
Area Below and Above.
The easiest and most frequent thing we do is find probabilities of events less extreme or more extreme than an event. We do this by using the zscore. Let's take the example of IQ scores. Most IQ tests have means of 100 and standard deviations of 15. Let's say you take an IQ test and get the score of 125. Are you super smart or just mediocre ? (of course you're smart, you're reading this!).
To find your relative standing we convert your score to a zscore using the formula :
z = (125100)/15 = 1.6667
The zscore is the number of standard deviations you are from the mean of 0 (recall that by subtracting the mean and dividing the result by the standard deviation you convert your data to the standard normal distribution which has a mean of 0 and standard deviation of 1).
So you're 1.6667 standard deviations above the mean. We look up 1.667 in a table of normal values, use the Excel function =NORMSDIST(1.6667) or use the online calculator and we get .952213. That means you're in the 95th percentile or you have a higher IQ score than about 95% of the population (you go!).
Because the area under the normal curve (or the total probability space) adds up to 1, we can find the percent of the population with a higher IQ score than you. We just subtract the score from 1 = 1.952213 = .047787. So about 4.7% of the population has a higher IQ score than 125. You can see how these are the areas under the normal in the figure above. The very small white area on the right is 4.7% of the area and the large green part to the left represents 95.22% of the area.
Area between
It is also often the case that we want to know what percent of the population will score between two points. For example, maybe you think many of your friends might score between say 115 and 125. What percent of the population would we expect to score between these values?
To find the area between two points we :
convert each raw score to a zscore
find the area for the two zscores
subtract the smaller area from the larger area
The zscores are (115100)/15 = 1 and we already calculated the zscore for 125 = (125100)/15 = 1.6667. Looking up the areas we find .9522 and .8413. Subtracting the smaller from larger we get .9522.8413 = .1109. Or about 11% of the population would score between a 115 and 125.
If you need more practice with finding areas with zscores, I put together a
Crash Course in Zscores
which provides a visual and easytofollow guide with plenty of practice understanding the normal curve and zscores.
View All Tutorials
How well did you understand this lesson?
Avg. Rating 7.89 (715)
Not at all
Neutral
Extremely
0
1
2
3
4
5
6
7
8
9
10
What didn't make sense?
Name
Email
Not Published
Comment
To prevent comment spam, please answer the following question before submitting (tags not permitted) :
What is 2 + 4:
(enter the number)
July 14, 2017  hail satan wrote:
Hey Mercedes You have to use a standard normal distribution chart if u dont have a calculator. Believe me, that isn't something you want to solve urself. Just look it up on google and find an image
May 6, 2017  hamza benjamin wrote:
please i need help in this question: the mean length of a life of certain cutting tool is 41.5 hours with standard deviation of 2.5 hours. what is the probability that a simple random sample of size 50 drawn from this population would have a mean between 40.5 hours and 42 hours
October 27, 2016  Mercedes wrote:
So you're 1.6667 standard deviations above the mean. We look up 1.667 in a table of normal values, use the Excel function =NORMSDIST(1.6667) or use the online calculator and we get .952213 this doesn't help as I need to know how to find it myself or with a calculator of my own.
October 17, 2009  Susan wrote:
I am still a bit confused about when you are suppose to subtract the value from 1.