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Standard Deviation in Practice
Home Introduction to the Standard Deviation Why do you need a measure of Variability? Measuring the Average Distance to the Mean Variability Quiz Population versus Sample Standard Deviation Standard Deviation Calculation Standard Deviation Calculation Short-Cut Method The Standard Deviation with Excel and The Online Calculator Standard Deviation in Practice Standard Deviation QuizView All Tutorials
The Standard Deviation :: Standard Deviation Quiz
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If you have the variance, how do you get the standard deviation?












 
Standard Deviation in Practice
Home Introduction to the Standard Deviation Why do you need a measure of Variability? Measuring the Average Distance to the Mean Variability Quiz Population versus Sample Standard Deviation Standard Deviation Calculation Standard Deviation Calculation Short-Cut Method The Standard Deviation with Excel and The Online Calculator Standard Deviation in Practice Standard Deviation QuizView All Tutorials

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April 17, 2016 | Yasser wrote:
set [4,10,12,2,15,5] mean = 48/6 = 8 variance = [(4-8)^2 + (10-8)^2 + (12-8)^2 + (2-8)^2 + (15-8)^2 + (5-8)^2] / n-1 so variance = 130 / 5 = 26 std. dev = sqrt of variance so sqrt of 26 = 5.099
 
September 22, 2015 | Noah Krause wrote:
I still don't get it
 
November 22, 2014 | Kristen wrote:
I had a hard time understanding how you interpret the differences between samples Or at least understanding how to do so outside of the examples given.
 
May 8, 2009 | JQ wrote:
On the questions at the end, when you ask us to calculate the standard deviation, you don't specify whether it is sample or population. If I am just given a small set of numbers, rather than told I have a sample drawn from a larger population, shouldn't I assume that that set is the complete set, and therefore use population SD?