View Answered Questions
| No. & Date Asked | Question |
# 523 :: 11/24/08
 |
Use the given degree of confidence and sample data to construct a confidence interval for the population mean x. Assume that the population has a norm. . .
Confidence Intervals,
TINV |
# 505 :: 11/11/08
|
Calculate a 98% confidence interval for the following data 15.7,15.7,15.5,15.2,15.2,15.1,15.3.. . .
Confidence Intervals,
TINV,
Margin of Error,
t-statistic |
# 487 :: 10/28/08
|
Find a confidence interval for the mean assuming that each sample is from a normal population. Mean = 127, s = 27, n = 16. Find the 90% Confidence Int. . .
TINV,
t-distribution,
Confidence Intervals |
# 485 :: 10/27/08
|
Assume that the heights of 5 year old boys are normally distribued with a mean of 100cm and a standard deviation of 60. What is the sampling distribut. . .
TINV,
Confidence Intervals,
Standard Error of the Mean,
Standard Deviation of the Mean |
# 411 :: 9/24/08
|
Do you have any hints how I can figure out critical values at the significance level? Can you figure this out in excel or megastat? Is there a equat. . .
NORMSINV,
TINV |
# 399 :: 9/20/08
|
When you calculate CIs for time on task, I notice that you use the critical value from the t-distribution (TINV(0.05, degrees_of_freedom)). But when y. . .
exact interval,
Binomial Probability,
TINV,
Adjusted Wald,
Wald Interval,
Normal Approximation,
Small Sample |
# 212 :: 6/1/08
|
How would I figure out a 90% and 95% confidence interval for the below informaion? What would be the formula? Can I figure this out in Excel or Mega. . .
t-distribution,
Confidence Intervals,
TINV,
Margin of Error |
# 151 :: 4/14/08
|
A random sample of 25 households finds that an average of 2.3 people reside in each house (the standard deviation is 0.35). With a 95% confidence lev. . .
TINV,
t-statistic,
t-distribution,
Confidence Intervals,
Standard Error of the Mean,
Margin of Error |
